Respuesta :
Answer:
The largest is 25.
Step-by-step explanation:
If the first integer is x, the second is x+1 and the third is x+2.
When you multiply the largest by 4: (x+2)*4
It is 31 more than 3 times the smallest: (x+2)*4 = (x)*3+31
When you simplify you get : 4x+8 = 3x+31
Which means: x = 23
But since you want the largest you get: 23+2 = 25
The greatest of the three consecutive odd integers will be [tex]19[/tex].
What are integers ?
Integers are whole numbers that can be positive, negative and zero.
We have,
Let first integer [tex]= x[/tex]
Second integer [tex]= x+2[/tex]
Third integer [tex]= x+4[/tex]
Now,
According to the question,
[tex]4(x+4) = 3(x)+31[/tex]
Simplifying;
[tex]4x+16=3x+31[/tex]
Taking [tex]x[/tex] variable on one side and constant on the other;
[tex]4x-3x=31-16[/tex]
[tex]x=15[/tex]
So,
Now substitute the value of [tex]x[/tex] in every integer's equation,
i.e.
First integer [tex]= 15[/tex]
Second integer [tex]= 17[/tex]
Third integer [tex]= 19[/tex]
So, the greatest of the three consecutive odd integers is [tex]19[/tex].
Hence, we can say that the greatest of the three consecutive odd integers will be [tex]19[/tex].
To know more about integer click here
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