Answer:
[tex]\boxed {\boxed {\sf C. \ 9460 \ kJ}}[/tex]
Explanation:
The formula we must use is given to us:
[tex]q=mL_{vapor}[/tex]
q is the energy, m is the mass, and L(vapor) is the latent heat of vaporization.
The energy is what we calculate and the mass is 2 kilograms. We need to find the latent heat of vaporization, which is on the table.
- We know the sample is copper.
- Find that element on the table, then the third box tells us it's latent heat of vaporization is 4730 kJ/kg
Now we know:
[tex]m= 2 \ kg \\L_{vapor}=4730 \ kJ/kg[/tex]
Substitute the values into the formula.
[tex]q=(2 \ kg ) * (4730 \ kJ/kg)[/tex]
Multiply. Note that the kilograms (kg) will cancel each other out.
[tex]q= 2* 4730 \ kJ[/tex]
[tex]q= 9460 \ kJ[/tex]
9460 kilojoules are required to vaporize 2 kilograms of copper.
