Respuesta :
Answer:
The equation in standard form is:
Rx+Py = -PR
Step-by-step explanation:
The slope-intercept form of the line equation
[tex]y = mx+b[/tex]
where
- m is the slope
- b is the y-intercept
Given
The y-intercept (0, -R)
The x-intercept (−P, 0)
Finding the slope between (0, -R) and (−P, 0)
[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:-R\right),\:\left(x_2,\:y_2\right)=\left(-P,\:0\right)[/tex]
[tex]m=\frac{0-\left(-R\right)}{-P-0}[/tex]
[tex]m=-\frac{R}{P}[/tex]
Thus, the slope between (0, -R) and (−P, 0) is:
[tex]m=-\frac{R}{P}[/tex]
We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.
We are given the y-intercept point (0, −R).
Thus, y-intercept b = -R
so substituting b = -R and [tex]m=-\frac{R}{P}[/tex] in the slope-intercept form to determine the line of the equation
[tex]y = mx+b[/tex]
[tex]y=-\frac{R}{P}x\:+\:\left(-R\right)[/tex]
[tex]y=-\frac{R}{P}x\:-R[/tex]
So, the slope-intercept form of the line equation is:
[tex]y=-\frac{R}{P}x\:-R[/tex]
Converting the slope-intercept form of the line equation into standard form
As we know that the equation in the standard form is
Ax+By=C
where x and y are variables and A, B and C are constants
As
[tex]y=-\frac{R}{P}x\:-R[/tex]
so converting into standard form
Multiply the equation by P
Py = -Rx - PR
Add -Rx to both sides
Rx+Py = -Rx - PR + -Rx
Rx+Py = -PR
Therefore, the equation in standard form is:
Rx+Py = -PR
Answer:
C.) Rx+Py = -PR
Step-by-step explanation:
I took the test and got it right.
