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How many moles of sulfur are in a 707 gram sample of sulfur?
a) 12.2 moles of sulfur
Ob) 52.1 moles of sulfur
c) 51.1 moles of sulfur
od) 22.1 moles of sulfur

Respuesta :

Space

Answer:

d) 22.1 moles of sulfur

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

707 g S (Sulfur)

Step 2: Identify Conversions

Molar Mass of S - 32.07 g/mol

Step 3: Convert

  1. Set up:                   [tex]\displaystyle 707 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})[/tex]
  2. Divide:                   [tex]\displaystyle 22.0455 \ mol \ S[/tex]

Step 4: Round

Our closest answer is d) 22.1 moles of sulfur

This is due to dividing different rounded values.

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf D. \ 22.1 \ moles \ of \ sulfur}}[/tex]

Explanation:

To convert from moles to grams, we must use the molar mass. This can be found on the Periodic Table.

We are given a sample of sulfur. Look for the symbol S on the table.

  • Sulfur (S): 32.07 g/mol

This tells us the mass of 1 mole of sulfur. Use this molar mass as a ratio.

[tex]\frac{32.07 \ g \ S}{1 \ mol \ S }[/tex]

Multiply by the given number of grams (707).

[tex]707 \ g \ S *\frac{32.07 \ g \ S}{1 \ mol \ S }[/tex]

Flip the fraction so the grams of sulfur will cancel out.

[tex]707 \ g \ S *\frac{ 1 \ mol \ S }{32.07 \ g \ S}[/tex]

[tex]707 *\frac{ 1 \ mol \ S }{32.07 }[/tex]

[tex]\frac{ 707 \ mol \ S }{32.07 }[/tex]

[tex]22.0455254 \ mol \ S[/tex]

The number we caluclated is the closest to answer choice D: 22.1 moles of sulfur

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