Answer:
Equation of the straight line passing through the point ( 1,2 ) and having the slope
x - √3y -1+2√3 =0
Step-by-step explanation:
Step(i):-
Given that the point (1,2) and an angle = ∝ = 30°
The slope of the line
m = tan 30°
[tex]m = \frac{1}{\sqrt{3} } }[/tex]
Step(ii):-
Equation of the straight line passing through the point ( 1,2 ) and having the slope
[tex]m = \frac{1}{\sqrt{3} } }[/tex]
y - y₁ = m(x-x₁)
y - 2 = [tex]\frac{1}{\sqrt{3} } }[/tex] ( x -1)
√3(y-2) = (x-1)
⇒ √3y - 2√3 = x -1
x - √3y -1+2√3 =0
