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3. A 0.145 kg ball moving horizontally at 20 m/s is struck by a bat that causes the ball to move in the

opposite direction at 15 m/s. If the ball and bat were in contact for 5 ms, how much force did the bat

apply to the ball?

Respuesta :

Answer:

F = 1015 N

Explanation:

Given that,

Mass of a ball, m = 0.145 kg

Initial speed, u = 20 m/s

Final speed, v = -15 m/s (as it moves in opposite direction)

The ball and bat were in contact for 5 ms

We need to find the force the bat applies to the bat. We know that,

F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.145\times (-15-20)}{5\times 10^{-3}}\\\\F=-1015\ N[/tex]

So, the bat will apply 1015 N force to the ball.

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