Answer:
[tex]Raise = 1391.85\mu F[/tex]
Explanation:
Given
[tex]Temperature = 20^{\circ} F[/tex]
[tex]Gas = 30ft^3[/tex]
[tex]Efficiency = 90\%[/tex]
Required
Determine the pounds of water
[tex]1031BTU = 1ft^3[/tex] of water
[tex]1\mu F = 20BTU[/tex] - The energy to raise 1 pound of water by 20F
The raise in pounds is then calculated as:
[tex]Raise = Efficiency * Energy * Volume(gas) * cubic\ of\ water[/tex]
This gives:
[tex]Raise = 90\%* \frac{1\mu F}{20BTU} * 30ft^3 * \frac{1031BTU}{1ft^3}[/tex]
[tex]Raise = 90\%* \frac{1\mu F}{20BTU} * 30 * \frac{1031BTU}{1}[/tex]
[tex]Raise = 90\%* \frac{1\mu F}{20} * 30 * \frac{1031}{1}[/tex]
[tex]Raise = 90\%* \frac{1\mu F}{20} * 30 * 1031[/tex]
[tex]Raise = 90\%* \frac{1\mu F}{20} * 30930[/tex]
[tex]Raise = 90\%* 1\mu F * 1546.5[/tex]
[tex]Raise = 1\mu F * 1391.85[/tex]
[tex]Raise = 1391.85\mu F[/tex]
