Answer:
50%
Explanation:
Draw a Punnett square to solve this problem (see photo).
Blood type O has two recessive alleles, represented by two lowercase “i”s.
Blood type Bi has a dominant allele shown by capital i with superscript B and a recessive allele “i”.
In the result, two boxes are “IB i” (for blood type Bi) and two boxes are “i i” (for blood type O).
The chance of having a child with blood type O is:
2/4 = 1/2 = 50%
Therefore, the chance of having a child with blood type O is 50%.
