Respuesta :

This question is incomplete, the complete question is;

The enthalpy change for the reaction between two molecules of carbon oxysulfide (COS) to form one molecule of CO₂ and one molecule of CS₂, as shown below, is -3.2 x 10⁻²⁴ kJ per molecule of COS.

The bond energy for the C-S bond in C=S has been determined to be 552 kJ/mol.

What is the apparent bond energy of a carbon-sulfur bond in COS?

NOTE: A C=O bond adjacent to another double bond is not the same as a C=O bond that is not adjacent to another double bond.  

Answer:

The apparent bond energy of a carbon–sulfur bond is 550.1 kJ/mole

Explanation:

Given the data in the question and the figure 8.122 in the image below;

the given reaction can be written as follows;

2COS -----→ CO₂ + CS₂

Δ[tex]H_{rxn}[/tex] = ∑ Bond Energy ( reactants) - ∑ Bond Energy (products)

= [ (2 × C=O) + (2 × C=S) ] - [ (2 × C=O) + ( 2 × C=S) ]

we know that;

Δ[tex]H_{rxn}[/tex]  = -3.2 x 10⁻²⁴ kJ per molecule

= -3.2 x 10⁻²⁴ kJ × 2 × 6.023 × 10²³ kJ/mole

= -3.85 kJ/mole

Hence;

-3.85 kJ/mole = (2 × C=S)[tex]_{reactant}[/tex] - ( 2 × C=S)[tex]_{product}[/tex]

-3.85 kJ/mole = (2 × C=S)[tex]_{reactant}[/tex] - ( 2 × 552 kJ/mole)

(2 × C=S)[tex]_{reactant}[/tex] = -3.85 kJ/mole + 1104 kJ /mole

(2 × C=S)[tex]_{reactant}[/tex]  = 1100.15 kJ/mole

2 × ( C=S)[tex]_{reactant}[/tex] = 1100.15 kJ/mole

( C=S)[tex]_{reactant}[/tex] = 1100.15 kJ/mole / 2

( C=S)[tex]_{reactant}[/tex] = 550.1 kJ/mole

Therefore, the apparent bond energy of a carbon–sulfur bond is 550.1 kJ/mole

Ver imagen nuhulawal20
Lanuel

The apparent bond energy of a carbon-sulfur bond in COS is equal to 550.08 kJ/mol.

Given the following data:

  • Enthalpy change of reaction = [tex]-3.2 \times 10^{-24}\;kJ/mol.[/tex]
  • Bond energy of C=S = 552 kJ/mol.

Scientific data:

  • Avogadro's number = [tex]6.02 \times 10^{23}[/tex]

To determine the apparent bond energy of a carbon-sulfur bond in COS:

First of all, we would write a balanced chemical equation for the chemical reaction as follows:

                                   [tex]2COS \rightarrow CO_2 + CS_2[/tex]

The enthalpy change of two (2) moles of COS is:

[tex]\Delta H_{rxn} = -3.2 \times 10^{-24}\times 2 \times 6.02 \times 10^{23}\\\\\Delta H_{rxn} =-3.85\;kJ/mol.[/tex]

Mathematically, the enthalpy change of a chemical reaction is given by this equation:

[tex]\Delta H_{rxn} = \sum Bond\;Energy_{(reactansts)} - \sum Bond\;Energy_{(products)}\\\\\Delta H_{rxn} = [(2\times C=O)+ (2\times C=S)]- [(2\times C=O)+ (2\times C=S)][/tex]

Substituting the parameters into the equation, we have;

[tex]-3.85 = (2\times C=S)- [2\times 552]\\\\(2\times C=S)=1104-3.85\\\\(2\times C=S)=1100.15\\\\(C=S)=\frac{1100.15}{2} \\\\(C=S)=550.08\;kJ/mol[/tex]

Therefore, the apparent bond energy of a carbon-sulfur bond in COS is equal to 550.08 kJ/mol.

Read more: https://brainly.com/question/13197037

Complete Question:

The enthalpy change for the reaction between two molecules of carbon oxysulfide (COS) to form one molecule of [tex]CO_2[/tex] and one molecule of [tex]CS_2[/tex], as shown below, is [tex]-3.2 \times 10^{-24}[/tex] kJ per molecule of COS.  The bond energy for the C-S bond in C=S has been determined to be 552 kJ/mol. What is the apparent bond energy of a carbon-sulfur bond in COS?

[Note: A C=O bond adjacent to another double bond is not the same as a C=O bond that is not adjacent to another double bond.]