Answer:
K = 4.64 10⁻¹⁵ J
Explanation:
For this exercise we can use conservation of energy
starting point. Next to the negative plate
Em₀ = U = e V
final point. Right when you hit the positive plate
Emf = K = ½ m v²
energy is conserved
Em₀ = Em_f
e V = K
The electric potential is related to the electric field
V = - Ed
we substitute
-e E d = K
let's calculate
K = -1.6 10⁻¹⁹ (-2.9 10⁶) 1.0 10⁻²
K = 4.64 10⁻¹⁵ J
