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ABCD is a parallelogram
M is the midpoint of CB
N is the midpoint of AB
DA = a
DC = c
a) find, in terms of a and c, the vector of MN
b) show that CA is parralel to MN

ABCD is a parallelogram M is the midpoint of CB N is the midpoint of AB DA a DC c a find in terms of a and c the vector of MN b show that CA is parralel to MN class=

Respuesta :

Answer:

Part a)

MN = 0.5a-0.5c

Part b)

MN=0.5a-0.5c

CA=a-c

CA is parallel to MN because 2×MN = CA.

Step-by-step explanation:

Part a = We know that ABCD is a parallelogram (stated), thus opposite sides must be equal. So given that DA = a, CB = a, DC = c, AB = C.

MN = MB+BN, so as M is the midpoint of CB then MB = 1/2 a and as we are going against AB (we are doing BN) then it will be -0.5c as N is the midpoint of AB.

Part B= More of a mathswatch error, where you have to quite literally put the precise answer. CA = CD+DA so -c (as we are going the opposite way to DC) + a.

CA = -c+a

Now CA is a multiple of MN. But Mathswatch prefers if you say that CA is parallel to MN because MN times 2 is equal to CA

lhmarianateixeira

In this exercise we have to use the knowledge of parallelogram and vectors to give the values ​​of each one of them, like this:

A) MN = 0.5a-0.5c

B)CA is parallel to MN because 2×MN = CA.

First, we have to remember the definition of parallelogram:

  • A polygon is any flat closed shape made of straight line segments. A parallelogram is a polygon with 4 sides in which sides that don't touch each other are parallel.

A) We know that ABCD is a parallelogram, thus opposite sides must be equal. So given that:

[tex]DA = a,\\CB = a, \\DC = c, \\AB = C.[/tex]

[tex]MN = MB+BN\\MB = 1/2\\BN=-0.5c\\MN = 0.5a-0.5c[/tex]

B)Where you have to quite literally put the precise answer, so we have that:

[tex]CA = CD+DA \\CD=-c\\DA=a\\CA = -c+a\\[/tex]

See more about parallelogram at brainly.com/question/555467

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