contestada

A circle is shown. A secant and tangent intersect at a point outside of the circle. The length of the tangent is x + 2, the length of the external part of the secant is x, and the length of the internal part of the secant is x + 4.
Which equation results from applying the secant and tangent segment theorem to this figure?

x(x + 2) = (x + 4)
x(x + 4) = (x + 2)
x(x + 4) = (x + 2)2
x(2x + 4) = (x + 2)2

Respuesta :

Answer:

its d on edge

Step-by-step explanation:

d on edge

x(2x + 4) = (x + 2)²

What is tangent and secant theorem?

​If a tangent and a secant intersect in the exterior of a circle, then the square of the measure of the tangent is equal to the product of the measures of the secant and its external secant segment.

Let length of tangent be l = x+2

Length of exterior part of secant =m=x

Length of interior part of secant =n=x+4

Now using the secant intersection theorem, we have

l² =m(m+n)

(x+2)² = x (x+x+4)

x(2x + 4) = (x + 2)²

To learn more about the tangent and secant theorem refer to:

https://brainly.com/question/4494553

#SPJ2

Otras preguntas