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You want to reduce the size of a picture to place in a
small frame. You aren't sure what size to choose on
the photocopier, so you decide to reduce the picture
by 15% each time you scan it until you get it to the
size you want. If the picture was 10 inches long at the
start, how long is it after 3 scans?
y=
Equation Used:
; A=

You want to reduce the size of a picture to place in a small frame You arent sure what size to choose on the photocopier so you decide to reduce the picture by class=

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AnimalPost

Answer:

Exact answer: y = 6.14125 inches, not completely sure though.

Step-by-step explanation:

Assuming that r represents the rate, A represents the principal amount, and t represents the times scanned, we know that A = 10 inches, t = 3 scans, and r = 15% or 0.15

I'm not sure what y represents, but it seems to be the final size of the picture after the scans are performed, so the equation could be:

y = A × [tex](1-r)^{t}[/tex]

So, y = (10) × [tex](1 - 0.15)^{3}[/tex]

y = 10 × 0.85³

y = 6.14125 inches

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