Answer:
d = 40 m
Explanation:
Given that,
Force, F = 4000 N
Mass of a car, m = 800 kg
Initial velocity, u = 0 (at rest)
Final velocity, v = 20 m/s
We need to find the distance traveled. Force acting on a car is given by :
F = ma
Where
a is the acceleration of the car.
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{4000}{800}\\\\a=5\ m/s^2[/tex]
Let it has traveled d distance. Using third equation of motion.
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(20)^2-(0)^2}{2\times 5}\\\\d=40\ m[/tex]
So, the required distance is equal to 40 m.