Answer:
Volume of gas at 12°C = 1.31 Liters
Explanation:
Given:
V₁ = 1.25 liters
T₁ = 0°C = (0 + 273)K = 273K
V₂ = ?
T₂ = 12°C =(12 + 273)K = 285K
Charles Law => V ∝ T => V = k·T => k = V/T = constant at all T,V values
∴ k₁ = k₂ => V₁/T₁ = V₂/T₂ => V₂ = V₁T₂/T₁ = (1.25L x 285K)/273K = 1.304945055L (calculator answer)
final answer should be rounded to 3 sig. figs. based on given Vol(1) = 1.25L.
∴
