A spherical ball of wax with a radius of 5 inches is melted and poured into a container shaped like a rectangular prism with a 12 inch x 10 inch base. What is the height of the melted wax in the new shape?

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Answer:

4.36 in

Step-by-step explanation:

To solve this problem we first find the volume of the sphere using the volume formula, after this we set this volume equal to the volume container which is a rectangular prism. After this we simple solve for the height by dividing the volume of the sphere by 12*10 to get the height

So the steps should look like

(4/3)*π*5³=523.599 in³

523.599 in³=12*10*Height

(523.599/(12*10))=4.36 in

The height of the melted wax in the new shape is 4.363 inches if the spherical ball of wax is melted and shaped like a rectangular prism.

What is volume?

It is defined as a three-dimensional space enclosed by an object or thing.

We have a spherical ball of wax with a radius of 5 inches.

The ball of wax is melted and poured into a container shaped like a rectangular prism.

In this scenario the volume of the ball remains same.

Formula for finding the volume of the sphere is given by:

[tex]\rm V = \frac{4}{3} \pi r^3[/tex]

[tex]\rm V = \frac{4}{3} \pi 5^3[/tex]

V = 166.66π cubic inches

Formula for finding the volume of a rectangular prism is given by:

V = l×w×h

Where l is the length, w is the width, and h is the height of the rectangular prism.

166.66π = 12×10×h   (l = 12 inches, w = 10 inches, and V = 166.66 inches³)

h = 4.363 inches   (π = 3.1415)

Thus, the height of the melted wax in the new shape is 4.363 inches if the spherical ball of wax is melted and shaped like a rectangular prism.

Learn more about the volume here:

https://brainly.com/question/16788902