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A piece of art is in the shape of an equilateral triangle with sides of 13 in. Find the area
of the piece of art. Round your answer to the nearest tenth.

Respuesta :

abidemiokin

Answer:

73.2sq.in

Step-by-step explanation:

Area of the triangle = 1/2 * base * height

Get the height using the pythagras theorem

h^2 = 13^2 - (13/2)^2

h^2 = 169 - (6.5)^2

h^2 = 169 - 42.25

h = 11.26in

Area of the triangle = 1/2 * 13 * 11.26

Area of the triangle = 6.5 * 11.26

Area of the triangle = 73.2sq.in

Hence the area of the triangle to nearest tenth is  73.2sq.in

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