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In ΔPQR, \overline{PR} PR is extended through point R to point S, \text{m}\angle PQR = (2x+6)^{\circ}m∠PQR=(2x+6) ∘ , \text{m}\angle RPQ = (x-7)^{\circ}m∠RPQ=(x−7) ∘ , and \text{m}\angle QRS = (5x-17)^{\circ}m∠QRS=(5x−17) ∘ . What is the value of x?x?

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abidemiokin

The value of x according to the given information is 8

Sum of interior angle

The sum of interior angle of a triangle is equal to the exterior

Given the following

interior angles = PQR=(2x+6)  and ∠RPQ=(x−7)

exterior = m∠QRS=(5x−17)

According to the theorem

5x -17 = 2x+6+ x - 7

5x - 17 = 3x - 1

5x-3x = -1 + 17

2x = 16

x =8

Hence the value of x according to the given information is 8

Learn more on exterior angle theorem here; https://brainly.com/question/11900288

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