The correct answer is four times as much.
Let the friend's mass be m, then according to the question the bodybuilder's mass will be 2m.
Now they both cover the same distance but the bodybuilder takes 4s and his friend takes 2s. Hence, if the time taken by the friend is t then the bodybuilder takes 2t time.
That means if the velocity of the bodybuilder is v then the velocity of his friend will be 2v.
Now, Power is defined as the rate of work done.
P = W/t
and work done is the change in kinetic energy.
Now the power generated by the bodybuilder is:
[tex]P_{b}=\frac{\frac{1}{2}2mv^{2} }{2t} \\\\P_b=\frac{mv^2}{2t}[/tex] ............(1)
power generated by the friend is :
[tex]P_{f}=\frac{\frac{1}{2}m(2v)^{2} }{t} \\\\P_b=\frac{4mv^2}{2t}[/tex].............(2)
Comparing (1) and (2) we get:
The friend generates four times as much power as the bodybuilder.
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