Respuesta :
Answer: There are [tex]61.24 \times 10^{23}[/tex] molecules present in 183.2 grams of [tex]H_{2}O[/tex] gas.
Explanation:
Given: Mass = 183.2 g
Number of moles is the mass of substance divided by its molar mass.
As molar mass of water is 18 g/mol. Therefore, moles of [tex]H_{2}O[/tex] are calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{183.2 g}{18 g/mol}\\= 10.17 mol[/tex]
According to the mole concept, there are [tex]6.022 \times 10^{22}[/tex] molecules present in one mole of a substance.
Hence, molecules present in 10.17 moles are calculated as follows.
[tex]10.17 mol \times 6.022 \times 10^{23}\\= 61.24 \times 10^{23}[/tex]
Thus, we can conclude that there are [tex]61.24 \times 10^{23}[/tex] molecules present in 183.2 grams of [tex]H_{2}O[/tex] gas.
