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Suppose that the Department of Energy develops a new reversible engine that has a coefficient of performance (COP) of 4.0 when operated as a refrigerator and a COP of 5.0 when operated as a heat pump. What is its thermal efficiency when operated as a heat engine doing work

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hamzaahmeds

Answer:

η = 0.2 = 20%

Explanation:

The relationship between the thermal efficiency of a heat engine and the Coefficient of Performance (COP) of the corresponding Heat Pump is given as follows:

[tex]\eta = \frac{1}{COP_{HP}}[/tex]

where,

η = thermal efficiency = ?

[tex]COP_{HP}[/tex] = Coefficient of Performance of Heat Pump = 5

Therefore,

[tex]\eta = \frac{1}{5} \\\\[/tex]

η = 0.2 = 20%

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