Respuesta :
The [tex]HIGHEST[/tex] of these numbers is [tex]14[/tex]
Let the [tex]CONSECUTIVE[/tex] numbers be : [tex]a, a+1, a +2,a+3,a+4,a+5[/tex]
Taking the sum :
[tex]a + a + 1 + a + 2 + a + 3 + a + 4 + a + 5 = 69\\6a + 15 = 69\\6a = 69 - 15\\6a = 54\\a = 54 / 6\\a = 9[/tex]
[tex]HIGHEST[/tex] value = [tex]a + 5 = 9 + 5 = 14[/tex]
Hence, [tex]HIGHEST[/tex] value = [tex]14[/tex]
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