Answer:
[tex] \small \sf \: x = - 12 \: \: and \: y = 10[/tex]
Step-by-step explanation:
2x + 4y = 16.
-2x - 3y = -6
Add both equation ;
[tex] \small \sf \: \: \: \: \: 2x + 4y = 16 \\ + \small \sf \: \: \underline{ -2x - 3y = -6 }\\ \small \sf \: \: \: \: \: \underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \blue{y = 10}} [/tex]
Therefore , y = 10
Substitute the value of y in the first equation
2x + 4 = 16
2 x + 4 × (10) = 16
2x + 40 = 16
subtract 40 from both side
2x + 40 - 40 = 16 - 40
2x = - 24
divide each side by 2
2x/ 2 = - 24 / 2
x = - 12
