Respuesta :

AlexTrusk

I guess you are stuck with 7., because I don't see any notes there.

[tex] \sqrt{2c + 3} = 5[/tex]

square both sides

[tex] { ( \sqrt{2c + 3) } }^{2} = {(5)}^{2} [/tex]

the root and the square cancel each other

2c + 3 = 25

subtract 3 on both sides

2c = 22

devide by two on both sides

c = 11

hope this helps you. have a nice day:)

CoastsideDad

Answer:

a) 4[tex]x^{2}[/tex] -4x + 1 = 0     (standard form. Just subtract 3 from both sides)

b) Vertex ([tex]\frac{1}{2}[/tex],0)

c) c = 11

Step-by-step explanation:

You got the line of symmetry correct.

Vertex looks good.

c) square both sides. solve for c.

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