Answer:
[tex]\displaystyle \frac{4y}{y+3}[/tex]
Step-by-step explanation:
Hi there!
[tex]\displaystyle \frac{2y}{y-3}*\frac{4y-12}{2y+6}[/tex]
Factor the second fraction:
[tex]= \displaystyle \frac{2y}{y-3}*\frac{4(y-3)}{2(y+3)}[/tex]
Simplify:
[tex]= \displaystyle \frac{2y}{y-3}*\frac{2(y-3)}{(y+3)}[/tex]
Multiply:
[tex]= \displaystyle \frac{2y*2(y-3)}{(y-3)(y+3)}\\\\= \displaystyle \frac{4y(y-3)}{(y-3)(y+3)}[/tex]
Simplify:
[tex]= \displaystyle \frac{4y}{y+3}[/tex]
I hope this helps!
