The magnitude of the resulting acceleration of the block is 6.14 m/s².
The given parameters;
- mass of the block, m = 2.2 kg
- horizontal force on the block, F = 27 N
- force below the horizontal, 81 N at 60⁰
The net horizontal force on the block is calculated as follows;
[tex]F_x = 27 \ - 81 \times cos (60)\\\\F_x = -13.5 \ N[/tex]
The acceleration of the block is calculated as follows;
[tex]a = \frac{-13.5}{2.2} \\\\a = - 6.14 \ m/s^2\\\\a = 6.14 \ m/s^2 \ to \ the \ left[/tex]
Thus, the magnitude of the resulting acceleration of the block is 6.14 m/s².
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