Using the uniform distribution, we have that:
a) The graph is sketched at the end of this answer.
b) 0.33 = 33% probability of generating a number between 0.01 and 0.34.
c) 0.05 = 5% probability of generating a number greater than 0.95.
An uniform distribution has two bounds, a and b.
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
The probability of finding a value above x is:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
In this problem, uniformly distributed between 0 and 1, thus [tex]a = 0, b = 1[/tex].
Item b:
[tex]P(0.01 \leq X \leq 0.34) = \frac{0.34 - 0.01}{1 - 0} = 0.33[/tex]
0.33 = 33% probability of generating a number between 0.01 and 0.34.
Item c:
[tex]P(X > 0.95) = \frac{1 - 0.95}{1 - 0} = 0.05[/tex]
0.05 = 5% probability of generating a number greater than 0.95.
A similar problem is given at https://brainly.com/question/24746230
