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A projectile is shot on level ground with a
horizontal velocity of 17 m/s and a vertical
velocity of 34 m/s.


-Find the time the projectile is in the air.
The acceleration due to gravity is 9.8 m/s2.
Answer in units of s.
-Find range R.
Answer in units of m.

A projectile is shot on level ground with a horizontal velocity of 17 ms and a vertical velocity of 34 ms Find the time the projectile is in the air The acceler class=

Respuesta :

Answer:

time rising = 34 / 9.8 = 3.47 sec

total time in air = 2 * 3.47 sec = 6.94 sec

(time rising must equal time falling)

R = 17 m/s * 6.94 s = 118 m

Can also use range formula

R = v^2 sin (2 theta) / g

tan theta = 34 / 17 = 2

theta = 63.4 deg

2 theta = 126.9 deg

sin 126.9 = .8

v^2 = 17^2 + 34^2 = 1445 m^2/s^2

R = 1445 * .8 / 9.8 = 118 m    agreeing with answer found above

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