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a ball is thrown straight downward with a speed of 0.80 meters per second. what is the speed of the ball 0.60 seconds after it is released? [ignore air resistance.]

Respuesta :

The speed of the ball 0.60 seconds after it is released is 6.8 m/s.

Newton's law of motion is given by:

v = u + gt

where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and t is the time.

Given that:

u = 0.8 m/s, g = 10 m/s², t = 0.6s. Hence:

v = 0.8 + 10(0.6)

v = 6.8 m/s

Therefore the speed of the ball 0.60 seconds after it is released is 6.8 m/s.

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