The distance between city A and city C is 6.71 units.
The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:
[tex]AB=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
A is located at (3,8) and a city B is located at (-3,20). Hence:
[tex]AB=\sqrt{(20-8)^2+(-3-3)^2}=13.42[/tex]
Since city C is halfway between city A and city B, hence:
AC = 13.42 / 2 = 6.71 units
The distance between city A and city C is 6.71 units.
Find out more on coordinate plane at: https://brainly.com/question/26100648
