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An object weighing 10 N swings at the end of a rope that is 0.72 m long as a simple pendulum. At the bottom of the of the swing, the tension in the string is 12 N. What is the maximum height above its lowest point that the object reaches

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Wolfyy

Answer:

1.20m/s

Explanation:

We can use the formula [ m = w/g ] and [ t - w = mv^2/r ] to solve.

Use the first formula.

m = 10/9.8

m = 1.02

Use the second formula.

12 - 10 = 1.02-v^2/0.72

2 = 1.02-v^2/0.72

1.04v^2 = 1.47

v^2 = 1.41

v = √1.41

v ≈ 1.20

Best of Luck!

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