We will see that the difference quotient of the given function is 5.
Here we want to find the difference quotient for the given function.
First, remember that the difference quotient is given by:
[tex]\lim_{h \to 0} \frac{f(x +h) - f(x)}{h}[/tex]
Now we want this for the function:
j(x) = 5x - 3
Then we will have:
[tex]\lim_{h \to 0} \frac{j(x +h) - j(x)}{h}\\\\\lim_{h \to 0} \frac{5*(x + h) -3 - 5*x + 3}{h}\\\\\lim_{h \to 0} \frac{5x + 5h - 3 - 5x + 3}{h}\\\\\lim_{h \to 0} \frac{5h}{h} = 5[/tex]
So the difference quotient of j(x) is 5.
If you want to learn more about difference quotients, you can read:
https://brainly.com/question/15166834
