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QUESTION 6 Calculate the molality of the HCI (aq) using the below information: Formula weight (g/mol): 36.465 Density of the solution (g/ml): 1.19 Weight %: 37.2 Molarity: 12.1 Your answer should have 3 sf) QUESTION 7 Calculate the molality of the NH3(aq) ​

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A 12.1 M HCl solution with a density of 1.19 g/mL has a molality of 16.1 m.

What is molality?

Molality is defined as the total moles of a solute contained in a kilogram of a solvent.

Let's suppose we have 1 L of the solution.

  • Step 1: Calculate the moles and mass of HCl (solute) in 1 L of solution.

The solution is 12.1 M, that is, there are 12.1 moles of HCl in 1 L of solution.

The molar mass of HCl is 36.465 g/mol.

12.1 mol × 36.465 g/mol = 441 g

  • Step 2: Calculate the mass corresponding to 1 L of solution.

The density of the solution is 1.19 g/mL.

1000 mL × 1.19 g/mL = 1190 g

  • Step 3: Calculate the mass of water (solvent) in 1190 g of solution.

In 1190 g of solution, there are 441 g of HCl.

mWater = 1190 g - 441 g = 749 g = 0.749 kg

  • Step 4: Calculate the molality (b) of the solution.

b = 12.1 mol / 0.749 kg = 16.1 m

A 12.1 M HCl solution with a density of 1.19 g/mL has a molality of 16.1 m.

Learn more about molality here: https://brainly.com/question/14623340

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