Answer:
You haven't provided a diagram, so I will calculate both acute angles and add an image to show where they are.
Angle the escalator makes with the floor
[tex]\implies sin(\theta)=\dfrac{45}{90}=\dfrac12[/tex]
[tex]\implies \theta=30 \textdegree[/tex]
Angle the escalator makes with the wall (vertical)
[tex]\implies cos(\theta)=\dfrac{45}{90}=\dfrac12[/tex]
[tex]\implies \theta=60 \textdegree[/tex]
