After the collision, the first cart is observed moving away from the second at a velocity of v/2. How much impulse did the second cart transfer to the first

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jamiesong3085 jamiesong3085

24-02-2022
Physics

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After the collision, the first cart is observed moving away from the second at a velocity of v/2. How much impulse did the second cart transfer to the first

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asuwafohjames asuwafohjames · Answer 1 · 2022-03-07T10:55:13+01:00

The impulse transferred to the first cart by the second cart is 3mv/2 kgm/s.

What is impulse?

Impulse can be defined as the product of the mass and the change in velocity of a body.

The impulse transferred to the first cart by the second cart can be calculated using the formula below.

Formula:

I = m(v-u)............... Equation 1

Where:

I = Impulse transferred to the first cart by the second cart
m = mass of the first cart
v = Final velocity of the first cart
u = Initial velocity of the first cart.

From the question,

Given:

m = m kg
v = v m/s
u = -v/2 m/s (moving away)

Substitute these given data into equation 1

I = m[v-(-v/2)]
I = m(v+v/2)
I = m(3v/2)

I = 3mv/2 kgm/s

Hence, the impulse transferred to the first cart by the second cart is 3mv/2 kgm/s.
Learn more about impulse here: https://brainly.com/question/20586658

Complete question: consider two carts moving on a track. the first cart has a mass of m, and the second has a mass of 3m. the first mass is moving at a velocity v towards the second, which is stationary. after the collision, the first cart is observed moving away from the second at a velocity of v/2. how much impulse did the second cart transfer to the first?