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Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 3 m/s. How fast is the area of the spill increasing when the radius is 20 m

Respuesta :

Answer:

A = pi R^2

dA / dT = pi 2 R dR / dT = pi 2 R v

dA dT = pi * 2 * 20 * 3 = 377 m^2 / sec

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