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Calculate the amount of heat released when 27.0 g H2O is cooled from a liquid at 314 K to a solid at 263 K. Using the chart below, complete the steps to calculate te overall heat released in the process. Type kn your answers Using 3 digits on the right. ((below))

q1 = ___kJ
q2 = ___kJ
q3 = ___ kJ
q4 = ___kJ

Calculate the amount of heat released when 270 g H2O is cooled from a liquid at 314 K to a solid at 263 K Using the chart below complete the steps to calculate class=

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adeoladokun31

The amount of heat released is 45.89kj.

The process involved in the reaction are

1.H20(314k)

2. H20 in solid form at 263k

Q= [m×Cpl ×Tfinal -Tinitial) + ∆H fussion

Q= amount of heat released = ?

m = mass of water = 27 g

cp(l) = specific heat of liquid water = 4.184 J/gk

Cp(s) = specific heat of solid water = 2.093 J/gk

∆H fussion = enthalpy change for fusion = 40.7 KJ/mole = 40700 J/mole.

Therefore, Q= 27 × 4.184j/gk × (314-2173k) + 40700j + (27g × 2.093j/gk ×273-263k).

Q = 45896.798j

Therefore, 1kj is 1000j

Therefore, the amount of heat released is 45.89kj.

What is Heat of formation?

Heat of formation is the amount of heat absorbed or released by a mole of elements during chemical reaction.

Learn more about heat of formation from the link below.

https://brainly.com/question/518944

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