brookiepoohhh
contestada

a Show that the sum of any three
consecutive even integers is a multiple of 6.
b) Hence, or otherwise, work out what the
values of three consecutive even integers
must be if their sum is 6000.

Respuesta :

Answer:

Below.

Step-by-step explanation:

a) Let the numbers be n, n + 2 and n + 4

Sum = n + n + 2 + n + 4

= 3n + 6.

As n must be even (2, 4, 6 and so on) , 3n must be divisible by 6  and 3n + 6 is divisible by 6 also.

b) 3n + 6 = 6000

3n =  5994

n = 5994/3 = 1998

So the numbers are 1998, 2000 and 2002.

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