The other factor of the polynomial [tex]\rm x^2+8x+15[/tex] is ( x + 3 )
It is given that the polynomial [tex]\rm x^2+8x+15[/tex] has one factor that is [tex]\rm (x+5)[/tex].
It is required to find another factor of the above polynomial.
Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.
We have a polynomial of degree two:
[tex]\rm = x^2+8x+15[/tex]
By using the factorization method we get:
[tex]\rm = x^2+8x+15\\\rm = x^2+3x+5x+15\\\rm = x(x+3)+5(x+3)\\\rm = (x+3)(x+5)\\[/tex]
Thus, the other factor of the polynomial [tex]\rm x^2+8x+15[/tex] is ( x + 3 )
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