The image points of triangle reflected across the line y = -1 is D'(-1,-1) ,E'(1,-5) , F'(3, 0) .
What is image point?
The given point P is "reflected" in the mirror and appears on the other side of the line an equal distance it. Drag the point P to see this. The reflection of the point P over the line is by convention named P' (pronounced "P prime") and is called the "image" of point P.
According to the question
Triangle points given
D(-1,-1), E(1,3), F(3, -2)
and reflected across the line y = -1
As, we have to reflect from y = -1 , there will be no change in x axis in image points only y axis will be change .
D(-1,-1)
x axis = -1
y axis = -1
x' axis = -1
y' axis = distance from -1 to -1 = 0
therefore,
y' axis = -1
D'(-1,-1)
E(1,3)
x axis = 1
y axis = 3
x' axis = 1
y' axis = distance from 3 to -1 = |3 -(-1 ) |= 4 unit
therefore, 4 unit form -1 in negative
y' axis = - 5
E'(1,-5)
F(3, -2)
x axis = 3
y axis = -2
x' axis = 3
y' axis = distance from -2 to -1 = |-2 -(-1 )| = 1 unit
therefore, 1 unit form -1 in positive
y' axis = 0
F'(3, 0)
Hence, the image points of triangle reflected across the line y = -1 is D'(-1,-1) ,E'(1,-5) , F'(3, 0) .
To know more about image points here:
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