Respuesta :
Answer:
See below
Step-by-step explanation:
y = 3x -5 <===== multiply this equation by -2 to get
-2y = -6x+10 now add it to the other equation(this will ELIMINATE x)
y = 6x-8
-y = +2
y = -2 then sub this in to oneof the quations to find x = 1
the two points will intersect at x,y = 1,-2 (because this satisfies both of the equations)
PART A
We start with: y = 3x - 5 y = 6x - 8
Elimination:
- If we have two equations that = y, then we can make them equal each other:
- y = y
- 3x - 5 = 6x - 8
- We then collect the x term together:
- 3x - 6x = -8 + 5
- -3x = -3
- We can divide both sides by -3:
- x = 1
Substitution
- We can make one equation turn from a y= to an x=
- I decided to go with y = 3x - 5 (but it doesn't matter)
- We basically want to get it into x=
- y = 3x - 5
- y + 5 = 3x
- 3x = y + 5 (I'm just flipping the equation to get x on the left for easiness)
- We then divide both sides by 3:
- x = [tex]\frac{y + 5}{3}[/tex]
- Don't forget we've also got y = 6x - 8
- So we just put x in!
- y = 6 × [tex]\frac{y + 5}{3}[/tex] - 8
- y = [tex]\frac{6}{3}[/tex] × (y + 5) - 8
- y = 2 × (y + 5) - 8
- y = 2y + 10 - 8
- y = 2y + 2
- Rearrange to get y on one side:
- -y = 2
- Times both sides by -1:
- y = -2
- We can now go back to...
- x = [tex]\frac{y + 5}{3}[/tex]
- By putting y = -2 in:
- x = [tex]\frac{-2 + 5}{3}[/tex]
- x = [tex]\frac{3}{3}[/tex] = 1
PART B
- We can find where they intersect/overlap by using elimination/substiution
- We've already covered both, and we get x = 1
- This means we've already go the x-coordinate of our point where the lines meet
- (x, y) = (1, ?)
- We just put our value of x into either equation (since x = 1 is where they meet)
- I'll go with y = 6x - 8
- y = 6 × 1 - 8
- y = 6 - 8 = -2
- We end up with (1, -2)!!!
P.S.:
I've attached a screenshot of the graphs, notice how they meet at (1, -2)
