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A piece of machinery with a moment of inertia of 2.5 kg-m? rotates with a constant angular speed of 4.0
rad/s. A bolt loosens, causing a part of it to shift outward from the rotation axis, increasing the moment
of inertia by 1.0 kg-m². What would the new angular speed of the machinery be? (hint: Conservation
of momentum) 10 rad/s

Respuesta :

okpalawalter8

For a piece of machinery with a moment of inertia of 2.5 kg-m, new angular speed is mathematically given as

wf= 2.857 rad/s

What would the new angular speed of the machinery be?

Generally, the equation for the final angular speed  is mathematically given as

wf =  wi*(I1/I2)

Therefore

wf = 4.0*(2.5/3.5)

wf= 2.857 rad/s

In conclusion, the new angular speed

wf= 2.857 rad/s

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