Answer: 0.94 m/s
Explanation:
Mass of the first car:
m1=15,000 kg
Speed of the first car:
v1=2.5 m/s
Mass of the second car:
m2=25,000 kg
[tex]$Apply the conservation of momentum.$m_{1} v_{1}+m_{2} v_{2}=\left(m_{1}+m_{2}\right) v_{f}$Substitute the values.$\begin{aligned}(15000 \times 2.5)+(25000 \times 0) &=(15000+25000) v_{f} \\37500 &=40000 v_{f} \\v_{f} &=\frac{37500}{40000} \\&=0.9375 \\&=0.94 \mathrm{~m} / \mathrm{s}\end{aligned}$[/tex]
Therefore, the speed of the two cars coupled together after the collision is 0.94 m/s
