Create two Punnett squares for a fictional trait, “Star-bellied.” “S” represents a dominant star-bellied gene, and “s” represents the recessive trait. For the first Punnett square, the mother and father both have star bellies and the recessive gene; what is the chance their child will have a star-belly? For the second square, the mother has a star-belly and the recessive gene, and the father does not have a star-belly; what is the chance their child will have a star-belly?

Respuesta :

The Punnett squares provide information about the genotype and phenotype of individuals produced by the crosses. Cross 1) 3/4 = 75%. Cross 2) 2/4 = 50%.

What is a punnett square?

The Punnett square is a graphic representation that shows the different types of gamete combinations according to the alleles involved in a cross.

Punnett square shows the probabilities of getting offspring with different genotypes and their consequent phenotypes.

Available data:

  • S represents a dominant star-bellied gene
  • s represents the recessive trait.

We will assume this is a diallelic gene expressing complete dominance, this is, the dominant allele S completely hides the expression of the recessive allele s.

1st cross: mother and father both have star bellies and the recessive gene

Parentals) Ss   x    Ss

Gametes) S   s      S   s

Punnett square)    S      s

                      S     SS    Ss

                      s      Ss     ss

F1)  

   Genotype

   1/4 = 25% of the progeny is expected to be h0m0zyg0us dominant SS

   2/4 = 50%  of the progeny is expected to be heter0zyg0us Ss

   1/4 = 25% of the progeny is expected to be h0m0zyg0us recessive ss

   Phenotype

    3/4 =75% of the progeny is expected to have star bellies

    1/4 = 25% of the progeny is expected not to have star bellies

The chance their child will have a star-belly is 3/4 or 75%.

2nd cross: motherhas star bellies and the recessive gene and the father does not have a star-belly

Parentals) Ss   x    ss

Gametes) S   s     s   s

Punnett square)    S      s

                      s      Ss     ss

                      s      Ss     ss

F1)  

   Genotype

   2/4 = 50%  of the progeny is expected to be heter0zyg0us Ss

   2/4 = 50% of the progeny is expected to be h0m0zyg0us recessive ss

   Phenotype

    2/4 =50% of the progeny is expected to have star bellies

    2/4 = 50% of the progeny is expected not to have star bellies

The chance their child will have a star-belly is 2/4 or 50%

You can learn more about punnett squares at

https://brainly.com/question/25357981

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