The magnitude of reaction for the wheel is 250 N. The coefficient of kinetic energy between the wheel and ground is 0.32.
The friction is given as the stop force acted by the surface to the moving object.
[tex]v^2=u^2+2as[/tex]
Substituting the values of the initial velocity (u), final velocity (v) and the distance (s) at the contactless surface, the acceleration is given as:
[tex]0=(5)^2+2a\;\times\;4\\a=3.125\;\rm m/s^2[/tex]
The force can be given as:
[tex]F=ma\\F=80\;\text{kg}\;\times\;3.125\; \rm {m/s^2}\\\textit F=250\;N[/tex]
The magnitude of reaction for the wheel is 250 N.
[tex]\mu_kmgs=\dfrac{1}{2}mv^2\\[/tex]
Substituting the values:
[tex]\mu_k\;\times\;80\;\times\;9.8\;\times\;4=\dfrac{1}{2}\;\times\;80\;\times\;5^2\\\mu_k=\dfrac{5^2}{2\;\times\;9.8\;\times\;4}\\\mu_k=0.32[/tex]
The coefficient of kinetic energy between the wheel and ground is 0.32.
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