[tex]\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}} [/tex]
4 hours 12 minutes
Step-by-step explanation:
We need to convert time in hours by diving 15 by 60
[tex] \sf 2 \frac{15}{60} \\ \\ \sf 2 \frac{1}{4} [/tex]
as it is mixed fraction we will convert into improper
[tex] \sf \frac{(2 \times 4) + 1}{4} \\ \\ \sf time = \frac{9}{4} hours[/tex]
Now we need to find distance
[tex] \sf \green {distance = speed \times time}[/tex]
Here speed is 50km/h
[tex] \sf \implies distance = 50 \times \frac{9}{4}km \\ \\ \sf \implies distance = \frac{25 \times 9}{2}km \\ \\ \sf \implies distance = \frac{225}{2} km \\ \\ \sf \implies \red {distance = 112.5km}[/tex]
Now we have to have time at new speed at 27km/h
and distance is same
[tex] \sf \pink{ time = \frac{distance}{speed} }[/tex]
Now substituting the value of speed and distance
[tex] \sf \implies time = \frac{112.5}{27} [/tex]
Now we will remove point(.) from the distance by multiplying 10 with 27
[tex] \sf \implies time = \frac{1125}{27 \times 10} \\ \\ \sf \implies time = \frac{41.6}{10} [/tex]
now we will convert it into mixed fraction
[tex] \sf \implies time = 4 \frac{1}{5} hours [/tex]
Now we will convert fraction hours into minutes by multiply with 60
[tex] \sf \implies time = 4 \: hours \: \frac{1}{5} \times 60 \: minutes \\ \\ \sf \implies \orange{ time = 4 \: hours \: 12 \: minutes}[/tex]
