contestada

Question 6: Iron metal and chlorine gas react to form iron (III) chloride: 2 Fe(s) + 3 Cl2 (g) → 2 FeCl3 (s)

a) Beginning with 10.0 g of iron, what mass of Cl2 (g) is required for complete reaction?
 The amount of chlorine gas needed to react are 6.6 moles.


b) What mass of FeCl3 (s) can be produced?

c) If 10 g of each of iron and chlorine are combined, what is the theoretical yield of iron (III) chloride?

Respuesta :

shristiparmar1221

10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

What ois Theoretical yield ?

The quantity of a product obtained from a reaction is expressed in terms of the yield of the reaction.

The amount of product predicted by stoichiometry is called the theoretical yield, whereas the amount obtained actually is called the actual yield.

  • As 2 moles (111.68 g) of Fe consumes 213 gm of Cl₂ to produce 2FeCl₃

Therefore ,

10 gm of Fe will consumes = 213 / 111.68 x 10 = 19 gm Cl₂

  • As 2 moles (111.68 g) of Fe produces 2 mole (324 gm) of FeCl₃

Therefore ,

10 gm of Fe will produces = 324 / 111.68 x 10 = 29 gm FeCl₃

Hence , 10 gm of Fe will consumes 19 gm Cl₂ and will produces 29 gm FeCl₃.

Learn more about Theoretical yield here ;

https://brainly.com/question/12704041

#SPJ1

Otras preguntas