The remaining amount after 4 years is 1.25 kg
The half life of a function is represented as:
[tex]A = A_o * (1/2)^{t/h}[/tex]
Where
Ao represents the initial amount
So, we have:
[tex]A = 5 * (1/2)^{t/2}[/tex]
In 4 years, t = 4.
So, we have:
[tex]A = 5 * (1/2)^{4/2}[/tex]
This gives
[tex]A = 5 * (1/2)^2[/tex]
Evaluate the expression
A = 1.25
Hence, the remaining amount after 4 years is 1.25 kg
Read more about half life at:https://brainly.com/question/26148784
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