According to Charle's law equation, the volume of a sample of carbon dioxide will be 684.6 mL and the temperature will be 283.60 K.
According to Charles' Law, the volume of a gas container with a certain amount of gas within is precisely proportional to the temperature when the pressure is constant.
[tex]V_{1}[/tex] = 684.6 mL
[tex]V_{2}[/tex] = 933.9 mL
[tex]T_{1}[/tex] = ?
[tex]T_{2}[/tex] = 387 K
Using Charle's law equation
[tex]\frac{684.6}{T_{1} } = \frac{933.9}{387}[/tex]
[tex]T_{1} = \frac{2,64,862.8}{933.9}[/tex]
[tex]T_{1} = 283.60 K[/tex]
According to Charle's law equation, the temperature at 684.6 mL volume was 283.60 K.
For more information about Charle's law equation here
https://brainly.com/question/16927784
#SPJ4
