Respuesta :
If 2 grams of water absorbs 20 calories of heat (assume not during a state change), the resulting water temperature change is - 272.975 °C .
Calculation ,
Formula used : Q = m × Cp × change in temperature
Q = m × Cp × ΔT ( i )
Where Q is the heat supplied in calories = 20 cal ( given )
m is the mass of water in gram = 2 g ( given )
Cp is the specific heat capacity of water at constant pressure = 1 cal / gK ( known )
Thus , after putting the value of heat supplied in calories , mass of water and specific heat capacity of water in equation ( i ) we get the value of change in temperature .
1 cal / gK = 2 g × 20 cal × ΔT
ΔT = 1 cal / gK / 2 g × 20 cal = 0.025 K
ΔT = 0.025 K - 273 = - 272.975 °C
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